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Then, if we push it out, the amount of water we get at the bottom of the column is: $$\frac{mc^2}{2}\cdot\frac{V}{R^2}=\frac{1}{2}\cdot\frac{P}{R}$$ where $m$ is the mass, $V$ is the volume, $c$ is the speed of light, and $R$ is the radius. This all agrees with the diagram with the exception that I don't understand why there is a value before X/Y is reached that is higher than Z. So, if we take the height of Y as starting point, then we get a pressure of: $$\frac{1}{2}\cdot P_{g}\cdot\left(\frac{R}{2}-Y\right)$$ which actually is not 2/3rds of the initial pressure because the starting height of Y doesn't seem to change anything in the first calculation. So my question is: how do I get the second number (2/3rds) from this calculation? I want to understand why the pressure is 2/3rds when we go from Y to Z. Is it because of the top/bottom edge of the bucket that makes a difference? (note: The water in the bucket is confined to the area of the bucket, which the diagram doesn't show) A: Since gravity points opposite to the force of buoyancy, so there will be a little more water at the top and a little less water at the bottom of the bucket. The initial pressure at Y is 2/3 times higher than the final pressure at Z. It's not just the top, bottom are less. This is because the net force of gravity is lower if you look down, but towards the bottom What's New In Gradient Duotone Design Photoshop Action Free Download? Inhibition of expression of the Hsp90α and Hsp90β genes in PC-3 human prostate cancer cells by antisense oligonucleotides. The expression of the Hsp90α and Hsp90β genes is high in many human malignancies, including prostate cancer. 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